If it's not what You are looking for type in the equation solver your own equation and let us solve it.
22x^2+48x=0
a = 22; b = 48; c = 0;
Δ = b2-4ac
Δ = 482-4·22·0
Δ = 2304
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{2304}=48$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(48)-48}{2*22}=\frac{-96}{44} =-2+2/11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(48)+48}{2*22}=\frac{0}{44} =0 $
| 5(a-8)-7(5a-7)=69 | | 7y-2+4+3y=-25 | | 4.2x-3=0/5(8.4x+6) | | 6x-18=x | | 12+12=13x+12 | | -3(-2+9v)= | | 3x+13x-1=4(4x+7) | | 30b+53≥18b=83 | | 44x^2+23x=0 | | 36x=-60+x | | (25x+30)+(5x)=90 | | X+11=8x-6 | | 5(3x+6)=73 | | 3.50x+4=18 | | -12(g)=-144 | | 3(2x+7)=-45+18 | | -7-9f=-3f-1 | | 6x^2+81x-42=0 | | 1/4n=1000 | | -21a+3=-39 | | 30=6w=12 | | 8+7r-4=-2r=6+9r | | 4(2x+2)-6=10 | | 5x-3x+13=x+19 | | 2x+4x-3=5x | | 11x+7=11x-2 | | 6x-2+5=9 | | 8x-6x-12=-21x | | 120+.50x=80+.90x | | 15=x-22 | | 45+6-x/3=42 | | 3x+3x=4x+10 |